# Open starturl inside app

**URL:** <https://devforum.zoom.us/t/open-starturl-inside-app/49822>\
**Category:** Meeting SDK\
**Created:** [May 7, 2021, 9:11am UTC](https://devforum.zoom.us/t/open-starturl-inside-app/49822 "2021-05-07T09:11:45Z")\
**Posts on this page:** 3\
**Page:** 1

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**Author:** ![shraddhap](https://sea2.discourse-cdn.com/flex016/user_avatar/devforum.zoom.us/shraddhap/32/20675_2.png) [@shraddhap](https://devforum.zoom.us/u/shraddhap)\
**Post date:** [May 7, 2021, 9:11am UTC](https://devforum.zoom.us/t/open-starturl-inside-app/49822/1 "2021-05-07T09:11:45Z")

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**Description**  
Open zoom start link in Xamarin iOS/android app

**Which Mobile Client SDK version?**  
Xamarin.Android.Zoom and Xamarin.iOS.Zoom

**Additional context**

I have created a zoom meeting(using API) which gives me a start URL for the same meeting, by using the start URL I want to open zoom within my xamarin app to start the meeting as a host what I have to do for such a scenario?

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**Author:** ![jon.zoom](https://sea2.discourse-cdn.com/flex016/user_avatar/devforum.zoom.us/jon.zoom/32/13495_2.png) [@jon.zoom](https://devforum.zoom.us/u/jon.zoom)\
**Post date:** [May 7, 2021, 6:39pm UTC](https://devforum.zoom.us/t/open-starturl-inside-app/49822/2 "2021-05-07T18:39:27Z")

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Hi @shraddhap, thanks for the post.

To clarify, are you asking how it would be possible to start your app when the end user clicks on a given URL? Or how to pass the URL into the SDK?

Thanks!

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**Author:** ![system](https://us1.discourse-cdn.com/flex016/uploads/zoomdeveloper/original/3X/6/1/614bdd549b610bbaa46ff934617683a02bdaa03c.png) [@system](https://devforum.zoom.us/u/system)\
**Post date:** [June 7, 2021, 4:39am UTC](https://devforum.zoom.us/t/open-starturl-inside-app/49822/3 "2021-06-07T04:39:40Z")

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Closed on June 7, 2021, 4:39am UTC

This topic was automatically closed 30 days after the last reply. New replies are no longer allowed.
