# Sign out function

**URL:** <https://devforum.zoom.us/t/sign-out-function/34442>\
**Category:** API and Webhooks\
**Created:** [October 27, 2020, 4:01pm UTC](https://devforum.zoom.us/t/sign-out-function/34442 "2020-10-27T16:01:52Z")\
**Posts on this page:** 3\
**Page:** 1

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**Author:** ![m.yankovskyyuk](https://sea2.discourse-cdn.com/flex016/user_avatar/devforum.zoom.us/m.yankovskyyuk/32/1667_2.png) [@m.yankovskyyuk](https://devforum.zoom.us/u/m.yankovskyyuk)\
**Post date:** [October 27, 2020, 4:01pm UTC](https://devforum.zoom.us/t/sign-out-function/34442/1 "2020-10-27T16:01:52Z")

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**Description**  
Hello, hopefully just a simple question here. I have seen the user signed out webhook in the documentation, however I was wondering if there is an api method to allow user to sign out of zoom without going onto zoom webpage? Or do we simply need to direct them to zoom account page an ask them to log out there?

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**Author:** ![will.zoom](https://sea2.discourse-cdn.com/flex016/user_avatar/devforum.zoom.us/will.zoom/32/14417_2.png) [@will.zoom](https://devforum.zoom.us/u/will.zoom)\
**Post date:** [October 28, 2020, 4:26pm UTC](https://devforum.zoom.us/t/sign-out-function/34442/2 "2020-10-28T16:26:42Z")

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Hi @m.yankovskyyuk,

At the moment, sign out functionality is not available via API. You will need to have the user sign out from [zoom.us](http://zoom.us).

Thanks,  
Will

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**Author:** ![system](https://us1.discourse-cdn.com/flex016/uploads/zoomdeveloper/original/3X/6/1/614bdd549b610bbaa46ff934617683a02bdaa03c.png) [@system](https://devforum.zoom.us/u/system)\
**Post date:** [November 28, 2020, 2:26am UTC](https://devforum.zoom.us/t/sign-out-function/34442/3 "2020-11-28T02:26:49Z")

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Closed on November 28, 2020, 2:26am UTC

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