Hi Fred,
thank you for the answer, but it didn’t help. As I mentioned before, I’m using JWTUtil class from your demo. That class doesn’t have the “tpc” field in the payload. I added and tried again, but no success, the same error appear. Here is the whole class that generate token (I added just the TPC field)
public class JWTUtil {
final static String TAG = JWTUtil.class.getSimpleName();
final static long EXPIRED_TIME = 3600 * 4;
private static final String apiKey = "";
private static final String apiSecret = "";
//for sdk user to bind zoom id with app userId.
public static String customIdentity = "test_" + Build.MODEL;
public static String createJWTAccessToken() {
int version = BuildConfig.VERSION_CODE;
long iat = System.currentTimeMillis() / 1000;
long exp = iat + EXPIRED_TIME;
if (TextUtils.isEmpty(apiKey) || TextUtils.isEmpty(apiSecret)) {
return "";
}
JSONObject headerObject = new JSONObject();
JSONObject payLoadObject = new JSONObject();
try {
payLoadObject.put("app_key", apiKey);
payLoadObject.put("version", version);
payLoadObject.put("iat", iat);
payLoadObject.put("exp", exp);
payLoadObject.put("user_identity", customIdentity);
payLoadObject.put("tpc", customIdentity + "_topic");
} catch (Exception e) {
Log.e(TAG, e.toString());
}
try {
headerObject.put("alg", "HS256");
payLoadObject.put("typ", "JWT");
} catch (Exception e) {
Log.e(TAG, e.toString());
}
String payload = payLoadObject.toString();
String header = headerObject.toString();
try {
String headerBase64Str = Base64.encodeToString(header.getBytes("utf-8"), Base64.NO_WRAP | Base64.NO_PADDING | Base64.URL_SAFE);
String payloadBase64Str = Base64.encodeToString(payload.getBytes("utf-8"), Base64.NO_WRAP | Base64.NO_PADDING | Base64.URL_SAFE);
final Mac mac = Mac.getInstance("HmacSHA256");
SecretKeySpec secretKeySpec = new SecretKeySpec(apiSecret.getBytes(), "HmacSHA256");
mac.init(secretKeySpec);
byte[] digest = mac.doFinal((headerBase64Str + "." + payloadBase64Str).getBytes());
String token = headerBase64Str + "." + payloadBase64Str + "." + Base64.encodeToString(digest, Base64.NO_WRAP | Base64.NO_PADDING | Base64.URL_SAFE);
Log.d(JWTUtil.class.getName(), "createJWTAccessToken:" + token);
return token;
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (InvalidKeyException e) {
e.printStackTrace();
}
return null;
}
}
I’m sending the class without aoyKey and Secret, which I have entered in the project. I get both apiKey and Secret from https://marketplace.zoom.us/develop/apps/eScS4EAPRzuBU7RWW4erzw/credentials
Are this correct key and secret? Or we need to use something else?
we use “https://zoom.us” as domain, when we initialize the SDK.
Note that we create this application on zoom before we got access to InstantSDK demo. Initially we had access to the older version of the ZoomSDK. Can it make problem? Do we use wrong apiKey and secret or you need to enable something else for this application/account? If you want I can share our credentials on email.
